Fitting the m Function to 1 – r0 / r

Feed: Dr. Myron Evans
Posted on: Monday, July 18, 2011 10:50 PM
Author: metric345
Subject: Fitting the m Function to 1 – r0 / r

Many thanks, this version could perhaps be used in your section of UFT 189. What is being done here is to regard the 1 – r0 / r function as an approximation to the solution obtained from geometry. In UFT 190 we could use the geometrical solution (the double exponential solution) to produce orbital functions: the orbital velocity of a planet dr / dt, and then dr / d phi and d phi / dt, angle of deflection and relativistic time delay. In FT 108 a function was found for precessing ellipses spiralling inwards (binary pulsars). As in eq. (4) of UFT 190, d phi / dt can be used to define angular momentum, and this is a link to the theory of whirlpool galaxies, as in previous papers angular momentum is expressed as spacetime torsion. If the double exponential function is approximated by

m (r0, a) = 1 – r0 / r – a / r squared

the orbits of UFT 108 are obtained. What is happening here is that the double exponential function m (R) is being reparameterized in terms of r0 (the constant 2MG / c squared) and a This process could be continued by using

m (r0, a , b) = 1 – r0 / r – a / r squared – b / r cubed – …………..

which should produce a different kind of binary pulsar orbit, and so on.

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