Discussion of 326(5), Part Two

The p0 is the Newtonian momentum, so Eqs. (29) and (32) can be solved, p0 does not contain gamma but p contains gamma:

p = gamma p0 = gamma m v = h bar kappa

E = gamma m c squared = h bar omega

as in many previous UFT papers.

. The origin of the Lorentz factor gamma is relativistic, i. e.

c squared dtau squared = c squared dt squared – v squared dt squared

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