The answer is given in UFT247 and UFT248, which develop collision and transmutation processes in general, for any number of nuclear reaction products. The total force is calculated from the total energy of p and Ni(64). However Ni(64) is much heavier and generates a much greater force due to m space. In nuclear theory the Coulomb repulsion is treated differently for separate p and Ni(64) and for the combined p and Ni(64) (see latest note for UFT431).
Graphics of Eqs. (1) and (2) of Note 431(4)
Does the total energy E (eq.2) relate to the proton or the Ni nucleus? The nuclear mass m and relativistic momentum p has to be chosen appropriately. It seems that p may be negleced for v<<c.
Horst
Am 13.02.2019 um 11:40 schrieb Myron Evans:
Graphics of Eqs. (1) and (2) of Note 431(4)
It would be very interesting to plot Eqs. (1) and (2) as a function of m(r), dm(r) / dr and p, the linear relativistic momentum of the proton. Quantization of Eqs. (1) and (2) should produce a wealth of new information, also the extension of UFT246 UFT248 with m theory should give important results. I will look in to this extension next.