Archive for June, 2017

To Make Better Hires, Treat Job Seekers With Respect

Wednesday, June 28th, 2017

Your EQ can have a significant impact – positive or negative – on your workplace performance, not to mention your life in general.

a%3D560c96ed80d44f578914d89ef0cf0b61%26t%3Dnewsletter%26s%3DDaily%26u%3D5b61cf7e-5bb6-11e7-99ff-c81f66f3a9a0

Recruiter Today
calender
calender
calender
You may be one click away from a better job!
Let Recruiter sift through 6 million jobs daily and tell you about new opportunities in your area.
Create a new job alert today, and be the first to know about new local openings in your field of interest
Do it once,and you`re done!
SAMPLE JOB FOR THE KEYWORD “MANAGER”. CLICK TO CUSTOMIZE THE JOB AND LOCATION
Registered Nurse/RN – Clinical Operations Manager
NP Now
San Antonio, Texas
Restaurant General Manager
Twin Peaks Restaurant
Greenville, South Carolina
EDIT MY JOB ALERT
Success more
Emotional Intelligence: Where Do You Excel – and Where Do You Need a Little Work? [Infographic]
Emotional Intelligence: Where Do You Excel – and Where Do You Need a Little Work? [Infographic]
Inside Recruiting more
To Make Better Hires, Treat Job Seekers With Respect
To Make Better Hires, Treat Job Seekers With Respect
Top 10 | Get Hired | Inside Recruiting
The Innovators | Success | Smart Tech
Top 10 more
Top 10 Tech Tools for Remote Workers and Distributed Teams
Top 10 Tech Tools for Remote Workers and Distributed Teams
The Innovators more
The What, Why, and When of Payroll Outsourcing
The What, Why, and When of Payroll Outsourcing
inspiration
idea
Free eBook to The 2017 Staffing Agency Hiring Guide Using Data and Technology to Drive Success
idea
Webinar: Staying Power: How to Hire and Retain Great Talent
idea
Starting a Successful Recruiting Agency Engagement, Free BountyJobs Best Practices
idea
What You Need to Know About Mobile Recruiting
fb.png in.png goog.png twit.png
TELL A FRIEND

This email has been sent to you because you are a member of Recruiter.com.

Want to receive our newsletter daily, weekly or not at all? Change your newsletter settings here, or unsubscribe.

Do not reply to this email. If this email looks suspicious in any way, do not respond or perform any requested action. Recruiter will never request you to share your password or personal information in an email. Contact us with any issues.

Recruiter.com, Inc. © 2017 | 1533 New Britain Avenue, Second Floor, Farmington, CT 06032

Solution for Spin Connection

Wednesday, June 28th, 2017

I intend to work on this today, fixing the sign change error of the last note.

To: EMyrone@aol.com
Sent: 27/06/2017 18:36:37 GMT Daylight Time
Subj: Re: Solution for Spin Connection

This sounds interesting, then we have to compute bold B from the standing wave to see how this situation can be realized.

Horst

Am 27.06.2017 um 14:13 schrieb EMyrone:

I have solved Eqs. (16) to (23) by hand to find a standing wave solution for the Q vector. The spin connection in this case is the simple omega bold = kappa and omega sub zero = omega, so the spin connection is the four wave vector. The general solution can be found by computer and this does not look to be a difficult problem. This is well worth doing because the method gives the spin connection four vector and the kappa vector in a perfectly general way.

Checking Note 380(4)

Wednesday, June 28th, 2017

Right, agreed, this will be fixed in the final paper as usual. Our system of checking, graphics and computer algebra is also first class, and the entire theory is based on irrefutable Cartan geometry. Our papers have been refereed and checked hundreds of thousands of times by a vast and permanent readership coming from the best universities, institutes, corporations, military facilities and similar in the world. Our scientometrics are uniquely accurate and detailed.

To: EMyrone@aol.com
Sent: 27/06/2017 18:28:33 GMT Daylight Time
Subj: Re: Discussion of 380(4)

When inserting eqs. (10,11) into (9), I obtain the equation

curl (- omega sub 0 Q) – partial / partial t (omega x Q) = 0

which gives a sign change when moving the second term to the RHS.

Horst

Am 27.06.2017 um 10:16 schrieb EMyrone:

I think that Eq. (13) is OK, because it is derived from

curl (- omega sub 0 Q) = – partial / partial t (omega x Q)

To: EMyrone
Sent: 26/06/2017 15:44:41 GMT Daylight Time
Subj: Re Re: Discussion of 380(4)

Shouldn’t there be a minus sign in eq.(13)?

Horst

Am 26.06.2017 um 16:20 schrieb Horst Eckardt:

It seems that in eqs.(16-18) of the note the dime derivatives at the LHS are missing.

Horst

Am 26.06.2017 um 09:56 schrieb EMyrone:

Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A three-vector and the spin connection four-vector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.

To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.

It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(16-23) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.

Horst

Am 25.06.2017 um 10:25 schrieb EMyrone:

This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q three-vector and the four components of the spin connection four-vector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.

Daily Report 26/6/17

Wednesday, June 28th, 2017

The equivalent of 71,685 printed pages was downloaded (261.363 megabytes) from 1,831 memory files downloaded (hits) and 375 distinct visits each averaging 4.1 printed pages and 7 minutes, printed pages to hits ratio of 39.15, top referrals total of 2,254,288, main spiders Google, MSN and Yahoo. Top ten 2290, Collected ECE2 2160, Collected Evans Morris 858, Collected scientometrics 580, Barddoniaeth 468, Autobiography volumes one and two 459, Evans Equations 361, Principles of ECE 228, F3(Sp) 225, CEFE 169, UFT88 93, PECE 81, Engineering Model 66, ECE2 63, CV 61, 83Ref 43, MJE 42, Llais 37, UFT311 37, UFT321 21, UFT313 20, UFT314 40, UFT315 39, UFT316 29, UFT317 29, UFT318 21, UFT319 37, UFT320 23, UFT322 22, UFT323 30, UFT324 30, UFT325 39, UFT326 16, UFT327 17, UFT328 44, UFT329 32, UFT330 17, UFT331 42, UFT332 25, UFT333 13, UFT334 26, UFT335 31, UFT336 32, UFT337 16, UFT338 21, UFT339 13, UFT340 28, UFT341 33, UFT342 29, UFT343 35, UFT344 44, UFT345 42, UFT346 36, UFT347 45, UFT348 35, UFT349 42, UTF351 47, UFT352 74, UFT353 39, UFT354 45, UFT355 38, UFT356 51, UFT357 31, UFT358 63, UFT359 41, UFT360 31, UFT361 26, UFT362 39, UFT363 46, UFT364 52, UFT365 25, UFT366 63, UFT367 26, UFT368 46, UFT369 25, UFT370 23, UFT371 23, UFT372 40, UFT373 24, UFT374 33, UFT375 22, UFT376 15, UFT377 31, UFT378 36, UFT379 16 to date in June 2017. Tor Project Univeristy of Waterloo Canada general; Wolfram Company general; Johns Hopkins University Medicine UFT213; Association for the Union of Student Residences University of South Paris (Paris-Psud) UFT42. Intense interest all sectors, updated usage file attached for June 2017.

Unauthorized

This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn’t understand how to supply the credentials required.

Additionally, a 401 Unauthorized error was encountered while trying to use an ErrorDocument to handle the request.

Solution for Spin Connection

Tuesday, June 27th, 2017

I have solved Eqs. (16) to (23) by hand to find a standing wave solution for the Q vector. The spin connection in this case is the simple omega bold = kappa and omega sub zero = omega, so the spin connection is the four wave vector. The general solution can be found by computer and this does not look to be a difficult problem. This is well worth doing because the method gives the spin connection four vector and the kappa vector in a perfectly general way.

Another suggestion for solving the antigravity problem

Tuesday, June 27th, 2017

I agree that the spin connection vector omega bold is a universal geometrical property that is the same for electromagnetism and gravitation. So is omega sub 0. The rigorous answer is to solve Eqs. (16) to (23) of Note 280(4) for bold Q, bold omega, and omega sub 0, then find phi for gravitation from Eq. (10) of that note. Finally use Eq. (14) of Note 380(2) to find the electric charge density needed to cahnge the gravitational phi to any desired value. Alternatively find bold omega from solving Eqs. (16) to (23) simultaneously, then use a model charge density in Eq. (14) to find phi. These are only two out of many possibilities. The set of Eqs. (16) to (23) can be simplified by intelligent approximation. I will think about this next. The give the gravitational vector potential Q (t, X, Y, Z) in a completely general way.

To: EMyrone@aol.com
Sent: 26/06/2017 20:00:53 GMT Daylight Time
Subj: Re: Another suggestion for solving the antigravity problem

A simple solution could be looking as follows:
The gravitational acceleration is

g = – nabla Phi + bold omega * Phi

with spin connection omega and gravitational potential Phi. Since there is only one space geometry, there is only one and the same omega for gravitation and electromagnetism. If it is possible to enhance bold omega significantly by electromagnetism, this should have an impact on g. So one of the equations (the above one) is nearly trivial. The question is how to construct an additional bold omega by electromagnetism. My idea was by a rotating magnetic field. But how to compute this? We need a quantitative theory.

Horst

Am 26.06.2017 um 10:11 schrieb EMyrone:

Agreed with this, Note 380(4) can be appleid to this anti gravity problem in order to simulate the apparatus and optimize conditions for counter gravitation. Note 380(4) used the homogeneous field equations of ECE2 gravitation:

del cap omega = 0

curl g + partial cap omega / partial t = 0

and the antisymmetry laws from

cap omega = curl Q – omega x Q

Here cap omega is the gravitomagnetic field, g is the gravitational field, Q is the gravitational vector potential, and omega the space part of the spin connection four vector. The inhomogeneous laws of ECE2 gravitation were not used in Note 380(4), and it was shown that the above three equations are sufficient to completely determine Q and the spin connection four vector. Having found them, they can be used in the inhomogeneous laws, the ECE2 gravitational Coulomb law and Ampere Maxwell law. Exactly the same remarks apply to ECE2 electromagnetism, and combinations of electromagnetism and gravitation. This ought to produce efficient counter gravitational designs. We can describe any existing counter gravitational apparatus with these powerful ECE2 equations.

To: EMyrone
Sent: 25/06/2017 16:01:12 GMT Daylight Time
Subj: Another suggestion for solving the antigravity problem

There are rumours out that antigravity can be achieved by rotating
magnetic fields (like in a 3-phase motor). In this case the spin
connection is the vector of the rotation axis if I see this right. So we
have a predefined bold omega and can apply the Faraday and/or
Ampere-Maxwell law to find bold A and bold Q. Perhaps worth a thought. I
am not sure if the coupling from e-m to gravity can be applied in the
same way as before.

Horst

Discussion of 380(4)

Tuesday, June 27th, 2017

I think that Eq. (13) is OK, because it is derived from

curl (- omega sub 0 Q) = – partial / partial t (omega x Q)

To: EMyrone@aol.com
Sent: 26/06/2017 15:44:41 GMT Daylight Time
Subj: Re Re: Discussion of 380(4)

Shouldn’t there be a minus sign in eq.(13)?

Horst

Am 26.06.2017 um 16:20 schrieb Horst Eckardt:

It seems that in eqs.(16-18) of the note the dime derivatives at the LHS are missing.

Horst

Am 26.06.2017 um 09:56 schrieb EMyrone:

Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A three-vector and the spin connection four-vector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.

To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.

It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(16-23) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.

Horst

Am 25.06.2017 um 10:25 schrieb EMyrone:

This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q three-vector and the four components of the spin connection four-vector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.

Discussion of 380(4)

Tuesday, June 27th, 2017

Many thanks again and agreed, they can be reinstated in the final manuscript.

To: EMyrone@aol.com
Sent: 26/06/2017 15:19:53 GMT Daylight Time
Subj: Re: Discussion of 380(4)

It seems that in eqs.(16-18) of the note the dime derivatives at the LHS are missing.

Horst

Am 26.06.2017 um 09:56 schrieb EMyrone:

Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A three-vector and the spin connection four-vector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.

To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.

It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(16-23) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.

Horst

Am 25.06.2017 um 10:25 schrieb EMyrone:

This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q three-vector and the four components of the spin connection four-vector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.

Daily Report Sunday 25/6/17

Tuesday, June 27th, 2017

There was very intense interest during the day. The equivalent of 1,763,028 printed pages was downloaded (6.428 gigabytes) from 7,624 memory files downloaded (hits) and 1,634 distinct visits each averaging 4.3 memory pages and 2 minutes, printed pages to hits ratio of 23.12, top referrals total of 2,254,011, main spiders Google, MSN and Yahoo. Top ten 2271, Collected ECE2 2152, Collected Evans Morris 825(est), Collected scientometrics 566, Barddoniaeth / Collected Poetry 465, Autobiography volumes one and two 455, Evans Equations 357, Principles of ECE 224, F3(Sp) 213, CEFE 170, Collected Eckart / Lindstrom 146, UFT88 92, PECE 79, Collected Proofs 65, ECE2 62, Engineering Model 60, CV 58, SCI 44, 83Ref 43, MJE 39, UFT311 37, Llais 35, PLENR 23,UFT321 21, UFT313 20, UFT314 38, UFT315 39, UFT316 29, UFT317 27, UFT318 21, UFT319 37, UFT320 22, UFT322 36, UFT323 30, UFT324 30, UFT325 38, UFT326 15, UFT327 17, UFT328 43, UFT329 31, UFT330 17, UFT331 41, UFT332 25, UFT333 13, UFT334 24, UFT335 31, UFT336 32, UFT337 16, UFT338 20, UFT339 13, UFT340 28, UFT341 32, UFT342 27, UFT343 35, UFT344 44, UFT345 41, UFT346 35, UFT347 44, UFT348 34, UFT349 42, UFT351 43, UFT352 72, UFT353 39, UFT354 43, UFT355 27, UFT356 50, UFT366 62, UFT367 26, UFT368 45, UFT369 25, UFT370 22, UFT371 22, UFT372 38, UFT373 23, UFT374 33, UFT375 22, UFT376 15, UFT377 31, UFT378 36, UFT379 16 to date in June 2017. University of Valencia UFT166(Sp), my page; Italian National Institute for Nuclear Physics (INFN) Ferrara UFT102; Philippines National Electrification Administration general. Intense interest all sectors, updated usage file attached for June 2017.

Unauthorized

This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn’t understand how to supply the credentials required.

Additionally, a 401 Unauthorized error was encountered while trying to use an ErrorDocument to handle the request.

Trajectory of Photons

Monday, June 26th, 2017

OK thanks, the trajectory of the photon is well known to be changed in a gravitational field, and that has been explained in several previous UFT papers. If gravitaton and electromagnetism interact, your idea could well work, the traejctory of the photon would be changed by a laser. Such experiments with two powerful interactig lasers have already been carried out. See the Omnia Opera and later papers for example. If one laser beam affects another your idea is right.

To: emyrone@aol.com, mail@horst-eckardt.de
Sent: 26/06/2017 06:04:56 GMT Daylight Time
Subj: Re: Discussion of 380(2): Combined Gravitation and Electromagnetism, Biefeld Brown

My point was not about photons being changed in mass but in trajectory.
For example a laser maybe useful in an experiment to measure electrogravitic effects due to light bending.

Sean

On June 23, 2017 at 1:37:34 AM, emyrone@aol.com (emyrone) wrote:

The photon is not charged, but in previous UFT papers and in ECE2 (UFT366) the ECE2 theory of light bending by gravitation is given.

Sent: 22/06/2017 20:33:49 GMT Daylight Time
Subj: Re: 380(2): Combined Gravitation and Electromagnetism, Biefeld Brown

If a local gravitational field can be altered by an electric potential can the path of light be warped as means of detection of the gravitational bending?

Sean

On June 21, 2017 at 5:40:42 AM, emyrone@aol.com (emyrone) wrote:

This note gives a scheme of computation on page 7 by which the problem can be solved completely and in general. There are enough equations to find all the unknowns, given of course the skilful use of the computer by co author Horst Eckardt. The Biefeld Brown effect is explained straightforwardly by Eq. (14), which shows that an electric charge density can affect the gravitational scalar potential and therefore can affect g. I did a lit search on the Biefeld Brown effect, it has recently been studied by the U. S. Army Research Laboratory. This report can be found by googling Biefeld Brown effect”, site four. There are various configuration which can all be explained by Eq. (14) – asymmetric electrodes and so on. In the inverse r limit the total potential energy is given by Eq. (19). This gives the planar orbital equations on page 4 of the Note. These can be solved numerically to give some very interesting orbits using the methods of UFT378. The lagrangian in this limit is Eq. (29) and the hamiltonian is Eq. (30). These describe the orbit of a mass m and charge e1 around a mass M and charge e2. If Sommerfeld quantization is applied this method gives the Sommerfeld atom. Otherwise in the classical limit it desribes the orbit of one charge with mass around another. The equations are given in a plane but can easily be extended to three dimensions. Eqs. (31) to (34), solved simultaneously and numerically with Eqs. ((37) and (39), the antisymmetry conditions, are six equations in six unknowns for gravitation and six equations in six unknowns for electromagnetism. These equations give the spin connections and vector potentials in general (three Cartesian components each).