Many thanks, a very useful result which I can use to calculate the velocity v with the Debye model.
In a message dated 29/01/2015 15:37:01 GMT Standard Time, writes:
Eq. (26) can be written as
v = c * n’/(n’^2+n”^2).
This is the realpart of the solution (25), see attached.
Horst
EMyrone@aol.com hat am 29. Januar 2015 um 15:54 geschrieben:
This is given by E = h bar omega = gamma m c squared, gamma = ( 1 – (v/c) squared) power minus half, and by the general expression (26) for photon velocity v in the presence of absorption. In this case it is no longer the simple c / v. Here m is photon mass. In the next note this set of fundamental optical equations will be solved to give the photon velocity in terms of the power absorption coefficient (27). So whenever there is absorption of any kind, photon mass can be calculated and inter alia photon mass always exists for any absorption. This completely refutes the standard model idea of massless photon in yet another way. Horst might like to plot the photon velocity v from eq. (26) in terms of real and imaginary parts of the refractive index. In the first instance these can be modelled, but they can be worked out completely as in the next note.
x=n1/(n2^2+n1^2)